Meta Llama 3.3 70B Instruct API
Run Meta-Llama-3.3-70B-Instruct through FastInfra's API.
Pay per token, no subscription, routed to the cheapest available provider.
Meta Llama 3.3 70B Instruct pricing
Billed per token used. Prices sync automatically from wholesale providers.
| Direction | Price per 1M tokens |
|---|---|
| Input | $0.63 |
| Output | $1.26 |
Served by 1 provider
Requests route to SambaNova by default (cheapest).
Pin a specific provider with the :provider suffix.
| Provider | Upstream model ID |
|---|---|
| sambanova | Meta-Llama-3.3-70B-Instruct |
Call Meta Llama 3.3 70B Instruct in 30 seconds
Works with any OpenAI SDK — change the base URL and API key only.
Python
from openai import OpenAI
client = OpenAI(api_key="YOUR_API_KEY", base_url="https://api.fastinfra.ai/v1")
response = client.chat.completions.create(
model="Meta-Llama-3.3-70B-Instruct",
messages=[{"role": "user", "content": "Hello!"}]
)
print(response.choices[0].message.content)curl
curl https://api.fastinfra.ai/v1/chat/completions \
-H "Authorization: Bearer YOUR_API_KEY" \
-H "Content-Type: application/json" \
-d '{
"model": "Meta-Llama-3.3-70B-Instruct",
"messages": [{"role": "user", "content": "Hello!"}]
}'Meta Llama 3.3 70B Instruct — common questions
How much does the Meta-Llama-3.3-70B-Instruct API cost?
On FastInfra, Meta-Llama-3.3-70B-Instruct costs $0.63/1M input, $1.26/1M output tokens. Billing is per token used, with no subscription.
Is Meta-Llama-3.3-70B-Instruct compatible with the OpenAI SDK?
Yes. FastInfra exposes Meta-Llama-3.3-70B-Instruct through an OpenAI-compatible endpoint at https://api.fastinfra.ai/v1 — point any OpenAI SDK at that base URL with a FastInfra API key and keep your existing code.
Which providers serve Meta-Llama-3.3-70B-Instruct?
Meta-Llama-3.3-70B-Instruct is available from 1 provider(s): sambanova. Requests route to SambaNova by default (cheapest); append ":provider" to the model ID to pin one.
Related models
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